• Free Test Series, Mock tests and Practice Tests
  • Time proven exam strategies
  • Exam analysis and simulated tests
  • Hand-on real time test experience

Recently Added Articles View More >>

NEW

Welcome to our 'Percentage Questions with Answers' blog, your go-to resource for mastering the art of percentages! Whether you're a student preparing for exams or someone looking to enhance their numerical skills.

Last week 114 Views
NEW

Welcome to our blog dedicated to Percentage Questions for Competitive Exams! Here, we unravel the complexities of percentage-based problems often encountered in various competitive exams. Whether you're preparing for government job exams, banking exams, or any other competitive test, mastering percentage calculations is essential.

6 months ago 997 Views
NEW

Methods of Calculating Percentage Increase - A Comprehensive Tutorial" is a detailed guide that explores various techniques for determining percentage growth in different contexts. Whether you're analyzing financial data, evaluating statistical trends, or measuring changes in quantities, this tutorial covers essential methods.

7 months ago 335 Views

Welcome to our Percentage Quiz Questions and Answers article! Whether you're a student preparing for exams, a professional brushing up on essential skills, or just someone who loves a good mental challenge, this Percentage Quiz Questions and Answers is designed for you.

7 months ago 1.1K Views

Percentage aptitude questions are a common component of many competitive exams, job interviews, and academic assessments. These types of questions require candidates to calculate percentages, proportions, ratios, and other related concepts to solve problems

Last year 2.0K Views
POPULAR

Percentage is a way of expressing a ratio in a mathematics subject. Also, percentage is very important in all competitive examinations, because other topics of mathematics also depend on percentage. Percent means per hundred (% = 1/100). Today in this article, I am providing percentage aptitude questions for all those students, who are preparing day-night.

4 years ago 14.6K Views
POPULAR

Percent is an important chapter of mathematics and its questions have been asked in the Competition Examination for many years. If you are preparing for SSC and banking exams then you should come to solve the percentage questions

4 years ago 13.5K Views
POPULAR

Don’t get stuck if you face difficulty in solving percentage questions, don't worry it happens. That time you just need to find percentage problems with solutions for bank exams or other competitive exams. So, here you can resolve your percentage problems with solutions for bank exams. With the help of these percentage problem solutions, you can improve...

4 years ago 10.2K Views

Most Popular Articles

POPULAR
Percentage Aptitude Questions for Competitive Exams Vikram Singh 4 years ago 14.6K Views
POPULAR
Percentage Shortcut Tricks For Bank PO Exams Vikram Singh 4 years ago 13.5K Views
POPULAR
Percentage problems with solutions for bank exams Vikram Singh 4 years ago 10.2K Views
Percentage Aptitude Questions Tricks for SSC Exam Rajesh Bhatia Last year 2.0K Views
Percentage Quiz Questions and Answers Rajesh Bhatia 7 months ago 1.1K Views
Percentage Questions for Competitive Exams Vikram Singh 6 months ago 997 Views
Percentage Questions with Answers Rajesh Bhatia Last week 114 Views

Most Popular Articles

Recently Added Questions

  • 1
    20 kg
    Correct
    Wrong
  • 2
    10 kg
    Correct
    Wrong
  • 3
    25 kg
    Correct
    Wrong
  • 4
    15 kg
    Correct
    Wrong
  • Show AnswerHide Answer
  • Workspace

Answer : 1
20 kg

Explanation :

Let's denote the weight of A as 𝑥x kg and the weight of B as 𝑦y kg.

Given:

  1. 𝑥+𝑦=80x+y=80 (Sum of weights of A and B is 80 kg)
  2. 0.5𝑥=56𝑦0.5x=65y (50% of A's weight is 5665 times the weight of B)

We can solve these two equations to find the values of 𝑥x and 𝑦y, and then calculate the difference between their weights.

From equation 2: 0.5𝑥=56𝑦0.5x=65y Multiply both sides by 2 to get rid of the fraction: 𝑥=56𝑦×2x=65y×2 𝑥=106𝑦x=610y 𝑥=53𝑦x=35y

Now substitute this expression for 𝑥x into equation 1: 53𝑦+𝑦=8035y+y=80 83𝑦=8038y=80 Multiply both sides by 3883: 𝑦=80×38y=80×83 𝑦=30y=30

Now that we have found the weight of B, we can find the weight of A using equation 1: 𝑥+30=80x+30=80 𝑥=80−30x=80−30 𝑥=50x=50

So, the weight of A is 50 kg and the weight of B is 30 kg.

Now, let's find the difference between their weights: Difference=Weight of A−Weight of BDifference=Weight of A−Weight of B Difference=50−30Difference=50−30 Difference=20Difference=20

Therefore, the difference between their weights is 20 kg.

  • 1
    72
    Correct
    Wrong
  • 2
    60
    Correct
    Wrong
  • 3
    75
    Correct
    Wrong
  • 4
    90
    Correct
    Wrong
  • Show AnswerHide Answer
  • Workspace

Answer : 1
72

  • 1
    150
    Correct
    Wrong
  • 2
    143
    Correct
    Wrong
  • 3
    140.55
    Correct
    Wrong
  • 4
    123.75
    Correct
    Wrong
  • Show AnswerHide Answer
  • Workspace

Answer : 4
123.75

  • 1
    5%
    Correct
    Wrong
  • 2
    15%
    Correct
    Wrong
  • 3
    25%
    Correct
    Wrong
  • 4
    10%
    Correct
    Wrong
  • Show AnswerHide Answer
  • Workspace

Answer : 4
10%

  • 1
    204
    Correct
    Wrong
  • 2
    198
    Correct
    Wrong
  • 3
    244
    Correct
    Wrong
  • 4
    156
    Correct
    Wrong
  • Show AnswerHide Answer
  • Workspace

Answer : 2
198

View more questions

Report Error

Please Enter Message
Error Reported Successfully

Report Error

Please Enter Message
Error Reported Successfully

Report Error

Please Enter Message
Error Reported Successfully

Report Error

Please Enter Message
Error Reported Successfully

Report Error

Please Enter Message
Error Reported Successfully