1113122110 In given series 2nd number gives number of  which digits present in the 1st number and so on continues for 3rd ,4th,... Here 1st no. has only one zero, so  2nd no. is 10 and 2nd no. has one 1 and one 0,so 3rd no. is 1110, so like that 5th no. has one 1,one 3,one 2,two 1's and one 0.So the next no. is 1113122110.

Answer: A) 35/36 Explanation: When two dice are thrown simultaneously, the probability is n(S) = 6x6 = 36 Required, the sum of the two numbers that turn up is less than 12 That can be done as n(E) = { (1,1), (1,2), (1,3), (1,4), (1,5), (1,6)(2,1), (2,2), (2,3), (2,4), (2,5), (2,6)(3,1), (3,2), (3,3), (3,4), (3,5), (3,6)(4,1), (4,2), (4,3), (4,4), (4,5), (4,6)(5,1), (5,2), (5,3), (5,4), (5,5), (5,6)(6,1), (6,2), (6,3), (6,4), (6,5) } = 35 Hence, required probability = n(E)/n(S) = 35/36.

Answer: A) 65 Explanation: The given number series is 8, 14, 24, 40, ? . It follows a pattern that, 8 8 x 1.5 + 2 = 14 14 x 1.5 + 3 = 24 24 x 1.5 + 4 = 40 40 x 1.5 + 5 = 65   Hence, the next number in the given number series is 65.