Bank Exams Practice Question and Answer

Q: The payment per hour for a daily-wages employee is increased by 33.33 and the working time is reduced by 33.33%. What is the percentage change in the employee's income ? 1274 0

  • 1
    11.11% decrease
    Correct
    Wrong
  • 2
    21.11% increase
    Correct
    Wrong
  • 3
    11.11% increase
    Correct
    Wrong
  • 4
    21.11% decrease
    Correct
    Wrong
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Answer : 1. "11.11% decrease"
Explanation :

Answer: A) 11.11% decrease Explanation: If earlier he is getting Rs. 1  per hr and working for 1 hr, income = Rs. 1Now he is getting Rs 1.3333 per hr and working for 0.66667 hrs Then income for 0.66667 hrs = Rs. 0.8889. If payment per hr is increased by 33.33 %  and working hours dereased by 33.33%, then 11.11 % decrease in income.

Q: If in the following set of numbers, the first and the third digits are interchanged in each number, which number will be second from the end if arranged in ascending order after interchanging the digits ? 585  546  514  404  206  369 1015 0

  • 1
    404
    Correct
    Wrong
  • 2
    585
    Correct
    Wrong
  • 3
    415
    Correct
    Wrong
  • 4
    602
    Correct
    Wrong
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Answer : 3. "415"
Explanation :

Answer: C) 415 Explanation: Given numbers are 585 546 514 404 206 369Then interchanging the 1st and 3rd digits of the given numbers, we get585 645 415 404 602 963Now, arranging them in ascending order963 645 602 585 415 404Then the last second number is 415.

Q: A farmer divides his herd of k cows among his 4 sons, so that one son gets one half of the herd, the second gets one-fourth, the third gets one-fifth and the fourth gets 9 cows. Then k is equal to ? 1140 0

  • 1
    160
    Correct
    Wrong
  • 2
    120
    Correct
    Wrong
  • 3
    140
    Correct
    Wrong
  • 4
    180
    Correct
    Wrong
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Answer : 4. "180"
Explanation :

Answer: D) 180 Explanation: Given total number of cows = kNow, 1st son share = k/22nd son share = k/43rd son share = k/54th son share = 9 (k) + (k/4) + (k/5) + 9 = k=> k - (19k/20) = 9=> (20k-19k)/20 = 9=> k = 180.

Q: The ratio of present ages of X and Y is 4:5. Which of the following can't be the ratio of ages of X and Y, 20 years ago ? 1453 0

  • 1
    2 : 5
    Correct
    Wrong
  • 2
    8 : 15
    Correct
    Wrong
  • 3
    9 : 10
    Correct
    Wrong
  • 4
    3 : 5
    Correct
    Wrong
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Answer : 3. "9 : 10"
Explanation :

Answer: C) 9 : 10 Explanation: The ratio of X and Y ages at present is 4:5.  Then, the ratio 20 years ago will not be more than the ratio at present. So, from the options 9:10 is not satifying => its ratio is 0.9 which is greater than presnt ratio of 0.8.

Q: There are 3 sections with 5 questions each. If four questions are selected from each section, the chance of getting different questions is ? 830 0

  • 1
    1000
    Correct
    Wrong
  • 2
    625
    Correct
    Wrong
  • 3
    525
    Correct
    Wrong
  • 4
    125
    Correct
    Wrong
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Answer : 4. "125"
Explanation :

Answer: D) 125 Explanation: Methods for selecting 4 questions out of 5 in the first section = 5 x 4 x 3 x 2 x 1/4 x 3 x 2 x 1 = 5. Similarly for other 2 sections also i.e 5 and 5 So total methods = 5 x 5 x 5 = 125.

Q: Vinod have 20 rupees. He bought 1, 2, 5 rupee stamps. They are different in numbers by the reason of no change, the shop keeper gives 3 one rupee stamps. So how many stamps Vinod have ? 3816 0

  • 1
    10
    Correct
    Wrong
  • 2
    18
    Correct
    Wrong
  • 3
    12
    Correct
    Wrong
  • 4
    15
    Correct
    Wrong
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Answer : 1. "10"
Explanation :

Answer: A) 10 Explanation: Given total rupees = 20 RsNo. of one rupee stamps = 3Now, remaining money = Rs. 17With that he buys only 2 and 5 rupee stampsLet number of Rs. 5 stamps = KLet number of Rs. 2 stamps = L5K + 2L = 17K = 3, L = 1 (possible)L = 6, K = 1 (possible)=> But given that they are different in number so, K is not equal to 3one rupee stamps = 32 two stamps = 65 rupee stamps = 1Total number of stamps = 10.

Q: There are 15 lines in plane. How many intersections (Maximum) can be made ? 1444 0

  • 1
    55
    Correct
    Wrong
  • 2
    105
    Correct
    Wrong
  • 3
    215
    Correct
    Wrong
  • 4
    148
    Correct
    Wrong
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Answer : 2. "105"
Explanation :

Answer: B) 105 Explanation: First line will cut all other 14, similarly second will cut 13, and so onTotal = 14+13+12+11+10+9+8+7+6+5+4+3+2+1 = 105.

Q: An Engine length 1000 m moving at 10 m/s. A bird is flying from engine to end with 'x' m/s and coming back at '2x' m/s. Take total time of bird travelling as 187.5 s. Find x and 2x in km/hr ? 1493 0

  • 1
    21.4 and 42.8
    Correct
    Wrong
  • 2
    25.2 and 50.4
    Correct
    Wrong
  • 3
    31.4208 and 62.8416
    Correct
    Wrong
  • 4
    33.12 and 66.24
    Correct
    Wrong
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Answer : 3. "31.4208 and 62.8416"
Explanation :

Answer: C) 31.4208 and 62.8416 Explanation: Birds speeds in mtrs/sec is 'x' and '2x' .While flying from Engine to end, relative speed = (x+10) m/secfrom end to engine, flying speed = (2x - 10) mtr/secso 1000/(x+10) + 1000/(2x-10) = 187.5 secssolving it, we getso x = 8.728 m/sec and 2x= 17.456 m/sec x = 31.4208 km/hr and 2x = 62.8416 km/hr.

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