(A) 20 min
(B) 50 min
(C) 60 min
(D) 40 min
Let 6 speed cover in x minute time
So that 5 speed cover in (x-10) minute time
So we can say
6x=5(x-10)
x=50 minute
(A) 1333.33 mt
(B) 1000 mt
(C) 7500 mt
(D) 1250 mt
First of all we convert unit in meter/sec
5 minute=5×60sec
(A) 45 km/ph
(B) 55 km/ph
(C) 60 km/ph
(D) 65 km/ph
Let the original speed of car is x km/hr. then,
(A) 9
(B) 10
(C) 12
(D) 20
Due to stoppages, it covers 9 km less.
Time taken to cover 9 km =
(A) 16.7 km
(B) 18.6 km
(C) 21.5 km
(D) 26.7 km
A walks in 4 hour is 4✖4 =16 km
After B start D=Speed×Time
16=6T
T=16/6
Then Distance covered by B is
D=ST
(A) 4.30 pm
(B) 4.45 pm
(C) 5 pm
(D) 5.51 pm
Suppose the thief has overtaken x hrs after 2.30 P.M.
Then, distance covered by the thief in x hours=distance covered by the owner in (x-1/2) hrs
so the thief is overtaken at 5 p.m.
(A) 30 km/ph
(B) 28.8 km/ph
(C) 32.88 km/ph
(D) None of these
(A) 900 km
(B) 945 km
(C) 990 km
(D) 1350 km
Distance=990 km
The average speed of a train is 3 times the average speed of car. The car covers a distance of 520 km in 8 hours. How much distance will the train cover in 13 hours?
(A) 2553 km
(B) 2585 km
(C) 2355 km
(D) 2535 km
(E) None of these
Train Car
3 1
Speed of car is =520/8=65km/h
so that speed of train = 65*3=195 km/hour
Distance covered by train=speed*time=195*13=2535 km
(A) 12 minutes
(B) 20 minutes
(C) 30 minutes
(D) 15 minutes
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