Most of the students have settled in their minds that math logical reasoning questions are difficult to solve in competitive exams. But I think, by practising these questions you can also solve maths questions easily in exams.
So, here I am sharing the selective and essential Maths Logical Reasoning Questions with Answers for Competitive Exams. You can easily improve your score in the competitive exam by taking an idea from these questions and you can increase your confidence by practising these questions.
Also, Read Latest Current Affairs Questions 2023: Current Affairs Today
"Unlock your potential and score high with our General Knowledge Mock Test and Current Affairs Mock Test!"
Q : A and B can do a piece of work in 72 days. B and C can do it in 120 days. A and C can do it in 90 days. In how many days all three together can do the work ?
(A) 80 days
(B) 100 days
(C) 60 days
(D) 150 days
A is as efficient as B and C together. Working together A and B can complete a work in 36 days and C alone can complete it in 60 days. A and C work together for 10 days. B alone will complete the remaining work in:
(A) 88 days
(B) 110 days
(C) 84 days
(D) 90 days
(E) 40 days
Three pipes A, B can fill the tank in 12, 20 hrs respectively and C can empty the tank in 30 hours. If the pipes are opened alternatively for 1 hour starting with A and drain pipe is kept open all the time. How much time will it take to fill the tank.
(A) 12
(B) 30
(C) 15
(D) 20
(E) None of these
A and B can do a work together in 18 days. A is three times as efficient as B. In how many days can B alone complete the work?
(A) 60 days
(B) 72 days
(C) 54 days
(D) 64 days
Let's denote the work rate of A as "A" and the work rate of B as "B." We know that A is three times as efficient as B, so we can write:
A = 3B
Now, we also know that A and B can do a work together in 18 days. The work rate of A and B combined is the sum of their individual work rates, which can be represented as:
A + B
Since they complete the work in 18 days together, we can write:
(A + B) = 1/18
Now, we want to find how long it would take B alone to complete the work. Let's denote that time as "x" days. The work rate of B alone would be:
B (work rate of B alone) = 1/x
Now, we have two equations:
A = 3B
(A + B) = 1/18
We can substitute the value of A from the first equation into the second equation:
(3B + B) = 1/18
Combine like terms:
4B = 1/18
Now, isolate B by dividing both sides by 4:
B = (1/18) / 4
B = 1/72
So, B's work rate is 1/72 of the work per day. To find how many days B alone can complete the work, take the reciprocal of B's work rate:
x (number of days for B alone) = 1 / (1/72)
x = 72
Therefore, it would take B alone 72 days to complete the work.
A alone can do a piece of work in 15 days, while B alone can do it in 20 days. They work together for 6 days and the rest of the work is done by C in 6 days. If they get Rs 800 for the whole work, how should they divide the money?
(A) Rs. 320, Rs. 240 and Rs. 240
(B) Rs. 640, Rs. 280 and Rs. 260
(C) Rs. 320, Rs. 420 and Rs. 360
(D) Rs. 360, Rs. 420 and Rs. 240
(E) Rs. 320, Rs. 240 and Rs. 720
Let's break down the problem step by step:
Now, let C complete the remaining 3/10 of the work in 6 days. We can calculate C's daily work rate:
C's daily work rate = Work done by C in 6 days / 6 C's daily work rate = (3/10) / 6 C's daily work rate = 1/20 of the work per day.
Now, let's calculate the total amount earned by each worker:
A's share: A worked for 6 days at a rate of 1/15 of the work per day, so he completed (6 * 1/15) = 2/5 of the work. A's share of the money is (2/5) * Rs 800 = Rs 320.
B's share: B worked for 6 days at a rate of 1/20 of the work per day, so he completed (6 * 1/20) = 3/10 of the work. B's share of the money is (3/10) * Rs 800 = Rs 240.
C's share: C worked for 6 days at a rate of 1/20 of the work per day, so he completed (6 * 1/20) = 3/10 of the work. C's share of the money is (3/10) * Rs 800 = Rs 240.
Now, to check if the total amount is correct, you can add up their individual shares:
Rs 320 (A) + Rs 240 (B) + Rs 240 (C) = Rs 800
So, they should divide the money as follows:
A, B and C can complete a work in 10, 20 and 30 days respectively. If D can destroy the same work in 15 days. Find the time taken by all of them to complete the whole work.
(A) 50/7days
(B) 60/7 days
(C) 20/3 days
(D) 40/7 days
(E) None of these
A and B together can do a piece of work in 12 days, A and C together can do the same work in 15 days. If B and C together can do the same work in 20 days, then in how many days A, B and C together can complete the same work?
(A) 8
(B) 6
(C) 10
(D) 9
(E) None of these
P can do a task in 30 days, Q is 50% more efficient than P, R can do the same work in 10 days less than Q if R and Q start task together and after X days they left the task and P completed the remaining task in (X + 8) days. then find the value of X?
(A) 2
(B) 4
(C) 5
(D) 8
(E) 6
A alone can complete a work in 25 days and B alone can do the same work in 20 days. A started the work and after working 7 days B joined A to finish the remaining work. In how many days, the total work will be finished?
(A) 8 days
(B) 15 days
(C) 9 days
(D) 12 days
(E) None of these
‘A’ can complete a work in 20 days while B is 25% more efficient than ‘A’. B worked for 6 days and left, the remaining work is completed by ‘C’ in 15 days. Find how many days ‘C’ can complete the whole work alone.
(A) 27 days
(B) 21 days
(C) 18 days
(D) 24 days
(E) 30 days
Get the Examsbook Prep App Today