A complete factorization of x4+64 is
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Q:
A complete factorization of x4+64 is
- 1$$\left(x^2+8 \right)^2 \ $$false
- 2$$\left(x^2+8 \right) \ (x^2-8)$$false
- 3$$\left(x^2-4x+8 \right) \ (x^2-4x-8)$$false
- 4$$\left(x^2+4x+8 \right) \ (x^2-4x+8)$$true
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