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Q: A is 3 times faster than B. If A can finish a work 32 days less than that of B, find the number of days need to finish the work if both are working together?

  • 1
    12 days
  • 2
    24 days
  • 3
    32 days
  • 4
    16 days
  • Show Answer
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Answer : 1. "12 days"
Explanation :

Answer: A) 12 days Explanation: It is given that efficiency ratio =3:1 so time ratio will be 1:3 (since work is same)   Also given that time diff = 32 days. ratio difference = 3-1 =2  2 ratio = 32 days 1 ratio = 16 days. So A will alone finish it in 16 days and B will finish it in 16*3 = 48 days.   Total work = LCM of 16 and 48 = 48. Total time = Total work/Total efficiency  ie; 48/4= 12 days.

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