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401

Q:

△ABC is right-angle triangle at B and tan A = $$3\over 4$$, then sin A + sin B + sin C will be equal to:

  • 1
    $$2{4\over 5}$$
  • 2
    $$2{2\over 5}$$
  • 3
    $$3{1\over 5}$$
  • 4
    $$1{1\over 5}$$
  • Show Answer
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Answer : 2. "$$2{2\over 5}$$"

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