From the top of an upright pole 17.75 m high, the angle of elevation of the top of an upright tower was 60⁰. If the tower was 57.75 m tall, how far away (in m) from the foot of the pole was the foot of the tower?
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Q:
From the top of an upright pole 17.75 m high, the angle of elevation of the top of an upright tower was 60⁰. If the tower was 57.75 m tall, how far away (in m) from the foot of the pole was the foot of the tower?
- 1$$40\sqrt {3} $$false
- 2$${151\sqrt {3}}\over 6 $$false
- 3$${77\over 4}\sqrt {3}$$false
- 4$${40\sqrt {3}}\over 3 $$true
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