From the top of an upright pole $$24\sqrt { 3} $$ feet high, the angle of elevation of the top of an upright tower was 600. If the foot of the pole was 60 feet away from the foot of the tower, what tall (in feet) was the tower?
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Q:
From the top of an upright pole $$24\sqrt { 3} $$ feet high, the angle of elevation of the top of an upright tower was 600. If the foot of the pole was 60 feet away from the foot of the tower, what tall (in feet) was the tower?
- 1$$84\sqrt { 3} $$true
- 2$$36\sqrt { 3} $$false
- 3$$44\sqrt { 3} $$false
- 4$$60\sqrt { 3} $$false
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