If $$ 3 ^{2x-y}=3^{x+y}=\sqrt{27}$$ then the value of y is
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Q:
If $$ 3 ^{2x-y}=3^{x+y}=\sqrt{27}$$ then the value of y is
- 1$$ {1\over2}$$true
- 2$$ {3\over2}$$false
- 3$$ {1\over8}$$false
- 4$$ {3\over4}$$false
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