If $$ {3^{a+3}×4^{a+6}×25^{a+1}\over{27}^{a-1}×8^{a-2}×125^{a+4}}={4\over15^{26}}$$ then the value of $$ {\sqrt{a+9}}$$.
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Q:
If $$ {3^{a+3}×4^{a+6}×25^{a+1}\over{27}^{a-1}×8^{a-2}×125^{a+4}}={4\over15^{26}}$$ then the value of $$ {\sqrt{a+9}}$$.
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