if $${5x-{5\over x}+6=0}$$, then $$x^2+{1\over x^2}$$ is
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Q:
if $${5x-{5\over x}+6=0}$$, then $$x^2+{1\over x^2}$$ is
- 1$$86\over11$$false
- 2$$43\over12$$false
- 3$$86\over25$$true
- 4$$81\over10$$false
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