If probability of drawing 1 ball such that it is not green is $$ { 4\over 5}$$, then sum of the number of red and white balls is
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Q:
If probability of drawing 1 ball such that it is not green is $$ { 4\over 5}$$, then sum of the number of red and white balls is
- 120false
- 230false
- 324true
- 416false
- 5None of thesefalse
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