If $${secθ+tanθ\over secθ-tanθ}={5\over 3}$$ then sinθ is equal to ;
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Q:
If $${secθ+tanθ\over secθ-tanθ}={5\over 3}$$ then sinθ is equal to ;
- 1$${1\over 4}$$true
- 2$${1\over 3}$$false
- 3$${2\over 3}$$false
- 4$${3\over 4}$$false
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