If $$ {x+3y-{2z\over 4}}=6$$ , $$ {x+{2\over 3}}(2y+3z)=33$$ and $$ {1\over 7}{(x+y+z)+2z=9}$$, then what is the value of $$ {46x+131y}$$?
5 3390 5f2bc64cb57ade01cafa6af6
Q:
If $$ {x+3y-{2z\over 4}}=6$$ , $$ {x+{2\over 3}}(2y+3z)=33$$ and $$ {1\over 7}{(x+y+z)+2z=9}$$, then what is the value of $$ {46x+131y}$$?
- 1364false
- 2414true
- 3384false
- 4464false
- Show Answer
- Workspace
- Discuss