If $$ {x+3y-{2z\over 4}}=6$$ , $$ {x+{2\over 3}}(2y+3z)=33$$ and $$ {1\over 7}{(x+y+z)+2z=9}$$, then what is the value of $$ {46x+131y}$$?
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Q:
If $$ {x+3y-{2z\over 4}}=6$$ , $$ {x+{2\over 3}}(2y+3z)=33$$ and $$ {1\over 7}{(x+y+z)+2z=9}$$, then what is the value of $$ {46x+131y}$$?
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