If x+y+z=6 and \(x^2\)+ \(y^2\) +\(z^2\)=20, then the value of \(x^3\)+\(y^3\)+\(z^3\)-3xyz is5
1370 5d1eecc4f5eae22172e6f3c4
Q: If x+y+z=6 and \(x^2\)+ \(y^2\) +\(z^2\)=20, then the value of \(x^3\)+\(y^3\)+\(z^3\)-3xyz is
- 164false
- 270false
- 372true
- 476false
- Show Answer
- Workspace
- Discuss