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Q: In a single throw of two dice , find the probability that neither a doublet nor a total of 8 will appear.

  • 1
    7/15
  • 2
    5/18
  • 3
    13/18
  • 4
    3/16
  • Show Answer
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Answer : 2. "5/18"
Explanation :

Answer: B) 5/18 Explanation: n(S) = 36   A = {(1, 1), (2, 2), (3, 3), (4, 4), (5, 5), (6, 6)}   B = { (2, 6), (3, 5), (4, 4), (5, 3), (6, 2) }   nA=6, nB=5, nA∩B=1   ∴Required probability = PA∪B    = PA+PB-PA∩B   =  636+536-136 = 518

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