In ∆ABC, ∠C=900, Point P and Q are on the sides AC and BC, respectively, such that AP:PC=BQ:QC=1:2.Then, $${AQ^2+BP^2}\over AB^2$$ is equal to:
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Q:
In ∆ABC, ∠C=900, Point P and Q are on the sides AC and BC, respectively, such that AP:PC=BQ:QC=1:2.Then, $${AQ^2+BP^2}\over AB^2$$ is equal to:
- 1$$8\over 3$$false
- 2$$4\over 3$$false
- 3$$13\over 9$$true
- 4$$4\over 9$$false
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