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Q:

PQRS is square whose side is 20 cm. By joining opposite vertices of PQRS are get four triangles. What is the sum of the perimeters of the four triangles?

  • 1
    $$ {40{\sqrt{2}}}$$
  • 2
    $$ {40{\sqrt{2}}}+ 40 $$
  • 3
    $$ {40{\sqrt{2}}}+ 80 $$
  • 4
    $$ {80{\sqrt{2}}}+ 80 $$
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Answer : 4. "$$ {80{\sqrt{2}}}+ 80 $$"

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