The average of 5 consecutive integers starting with ‘M’ is ‘K’. What is the average of 6 consecutive integers stating with (m+1)?
5 1049 5f4e19ed5e74bc4ee554e846
Q:
The average of 5 consecutive integers starting with ‘M’ is ‘K’. What is the average of 6 consecutive integers stating with (m+1)?
- 1$$ {2K-3}\over 2$$false
- 2$$ {2K+3}\over 2$$true
- 3$$ {2K-5}\over 2$$false
- 4$$ {2K+5}\over 2$$false
- Show Answer
- Workspace
- Discuss