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Q: The degree of dissociation (α) of a weak electrolyte, AxBy is related to van't Hoff factor (i) by the expression: 1. α=x+y+1i-1 2.α=x+y-1i-1 3. α=i-1x+y+1 4. α=i-1x+y-1

  • 1
    1 is correct
  • 2
    2 is correct
  • 3
    3 is correct
  • 4
    4 is correct
  • Show Answer
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Answer : 4. "4 is correct"
Explanation :

Answer: D) 4 is correct Explanation: Van't Hoff factor (i) = Observed Colligative PropertyNormal Colligative Property   AxBy1-α→xA+yxα+yB-xyα     Total Moles = 1-α+xα+yα = 1-αx+y-1   i=1+αx+y-11   ⇒α=i-1x+y-1

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