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Q: Tickets are numbered from 1 to 18 are mixed up together and then 9 tickets are drawn at random. Find the probability that the ticket has a number, which is a multiple of 2 or 3.

  • 1
    1/3
  • 2
    3/5
  • 3
    2/3
  • 4
    5/6
  • Show Answer
  • Workspace

Answer : 3. "2/3"
Explanation :

Answer: C) 2/3 Explanation: S = { 1, 2, 3, 4, .....18 }  => n(S) = 18   E1 = {2, 4, 6, 8, 10, 12, 14, 16, 18} => n(E1) = 9   E2 = {3, 6, 9, 12, 15, 18 } => n(E2) = 6    E3 =E1∩E2={6, 12, 18}  => n(E3) = 3   ∴E=E1 ∪ E2 = E1+E2-E3  => n(E) = 9 + 6 - 3 =12  where E = { 2, 3, 4, 6, 8, 9, 10, 12, 12, 14, 15, 16, 18 }   ∴P(E)=n(E)n(S)=1218=23

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