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Q: Two metallic plate of equal thickness and coefficient thermal conductivity K1 and K2 put together face to face. A common plate is constructed. What is equivalent K?

  • 1
    K1k2/k1+k2
  • 2
    2k1k2/k1+k2
  • 3
    K1+k2/k1k2
  • 4
    None
  • Show Answer
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Answer : 2. "2k1k2/k1+k2"
Explanation :

Answer: B) 2k1k2/k1+k2 Explanation: We know that,   The equivalent K =  L1 + L2L1K1+L2K2   where L1 & L2 are plate1 & Plate2 thicknesses, K1 & K2 are coefficient thermal conductivity of plate1 & Plate2 respectively.   But here L1 = L2 = L (say)   Then K = L+L/(L/K1 + L/K2)  =  2K1K2K1+K2

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