Two numbers x and y (x>y) such that their sum is equal to three times their difference. Then value of $$3xy\over 2(x^2-y^2$$ will be
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Q:
Two numbers x and y (x>y) such that their sum is equal to three times their difference. Then value of $$3xy\over 2(x^2-y^2$$ will be
- 1$$1{1\over 2} $$false
- 2$$1{1\over 3} $$false
- 3$$ {2\over 3}$$false
- 41true
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