Aptitude Questions Practice Question and Answer
8 4 4 5 Q:
5d4a91060c56ef19ba1db78d Answer : 1. "720"
4 4 4 4 Answer : 2. "3/2"
4 Answer : 2. "13"
Q: 240 metre long train running at 48 km/hour cross a platform in 39 seconds. What is the length of platform? 6121 05d198ffd1388cd24f08602fd
5d198ffd1388cd24f08602fd- 1520false
- 2280true
- 3480false
- 4270false
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Answer : 2. "280"
Q: A bus is running at 80 kmph without any stoppage. But, with stoppages its average speed is 60 km/hour. Find the time of stoppage by bus per hour. 2195 15d1994467619fe30b9d338a6
5d1994467619fe30b9d338a6- 112 minutesfalse
- 220 minutesfalse
- 330 minutesfalse
- 415 minutestrue
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Answer : 4. "15 minutes"
Q: In how many different ways can letters of the word ‘SECOND’ be arranged?
3289 05d4a91060c56ef19ba1db78d
5d4a91060c56ef19ba1db78d- 1720true
- 2120false
- 35040false
- 4270false
- 5None of the abovefalse
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Answer : 1. "720"
Explanation :
Number of letter in word ‘SECOND’ =6
The number of ways can the letters of word be arranged =6×5×4×3×2×1=720
Q: The ratio between boys and girl’s in a school is 4:6 respectively. If the number of boys is increased by 200 the ratio becomes 5:6 respectively. How many girls are there in the school? 2197 05d1b06bf1fc62311c773685b
5d1b06bf1fc62311c773685b- 11200true
- 2800false
- 31000false
- 4500false
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Answer : 1. "1200"
Q: A is thrice as fast as B. Together they can do a job in 15 days. In how many days will B finish the work? 2656 05d1488909aeb0a08f1e67455
5d1488909aeb0a08f1e67455- 140false
- 260true
- 330false
- 420false
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Answer : 2. "60"
Q: In a code, CORNER is written as GSVRIV. How can CENTRAL be written in that code? 5296 45b9a573dc4c55c03307a6f18
5b9a573dc4c55c03307a6f18- 1DFOUSBMfalse
- 2GIRXVEPtrue
- 3GNFJKERfalse
- 4None of thesefalse
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Answer : 2. "GIRXVEP"
Q: Find value of log27 +log 8 +log1000log 120 1721 15b5cc7d0e4d2b4197775120e
5b5cc7d0e4d2b4197775120e- 11/2false
- 23/2true
- 32false
- 42/3false
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Answer : 2. "3/2"
Explanation :
Answer: B) 3/2 Explanation: = log 33 + log 23+ log 103log10×3×22 =log33 12+log 23+log 10312log(10×3×22) =12log 33+3 log 2+12 log103log10+log3+log22 =32log 3 + 2 log 2 + log 10log 3 + 2 log 2 + log 10 = 32
Q: What is the number of digits in 333? Given that log3 = 0.47712? 5533 05b5cc7d0e4d2b41977751209
5b5cc7d0e4d2b41977751209- 112false
- 213true
- 314false
- 415false
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Answer : 2. "13"
Explanation :
Answer: B) 13 Explanation: Let Let x=333 = 333 Then, logx = 33 log3 = 27 x 0.47712 = 12.88224 Since the characteristic in the resultant value of log x is 12 ∴The number of digits in x is (12 + 1) = 13 Hence the required number of digits in 333is 13.
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