GRE Practice Question and Answer
8Q: In a town of 500 people, 285 read Hindu and 212 read Indian Express and 127 read Times of India, 20 read Hindu and Times of India and 29 read Hindu and Indian Express and 35 read Times of India and Indian express . 50 read no news paper . Then how many read only one paper ? 14262 05b5cc74fe4d2b4197774fb26
5b5cc74fe4d2b4197774fb26- 1123false
- 2231false
- 3312false
- 4321true
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Answer : 4. "321"
Explanation :
Answer: D) 321 Explanation: No. of people who read Hindu = 285No. of people who read TOI = 127No. of people who read IE = 212Now, No. of people who read Hindu and TOI both is = 20No. of people who read TOI and IE both is = 35No. of people who read Hindu and IE both is = 29Let No. of people who read Hindu , TOI and IE all is = x ;So, only Hindu is = 285-20-29-x = 236-x ;Only TOI is = 127-20-35-x = 72-x ;Only IE is = 212-35-29-x = 148-x ;Now, 236-x + 72-x + 148-x + 20 + 29 + 35 + x + 50 = 500 590 -2x = 500 So, x = 45 this is the value who read all the 3 dailies.So, No. of people who read only one paper is = 236-45 + 72-45 + 148-45 = 191 + 27 + 103 = 321.
Q: Sripad has scored average of 65 marks in three objects. In no subjects has he secured less than 58 marks. He has secured more marks in Maths than other two subjects. What could be his maximum score in Maths ? 1459 05b5cc74fe4d2b4197774fb21
5b5cc74fe4d2b4197774fb21- 179true
- 277false
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Answer : 1. "79"
Explanation :
Answer: A) 79 Explanation: Assuming Sripad has scored the least marks in subject other than science,Then the marks he could secure in other two are 58 each.Since the average mark of all the 3 subject is 65.i.e (58+58+x)/3 = 65116 + x = 195x = 79 marks. Therefore, the maximum marks he can score in maths is 79.
Q: If there are 150 questions in a 3 hr examination. Among these questions 50 are type A problems, which requires twice as much as time be spent on the rest of the type B problems. How many minutes should be spent on type A problems ? 3547 05b5cc74fe4d2b4197774fb1c
5b5cc74fe4d2b4197774fb1c- 175 minfalse
- 282 minfalse
- 390 mintrue
- 4101 minfalse
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Answer : 3. "90 min"
Explanation :
Answer: C) 90 min Explanation: Let X = Time taken for each of Type B Problems(100 Problems)And 2X = Time taken for each of Type A problems(50 problems) Total time period = 3hrs = 3 x 60min = 180 minutes 100X + 50(2X) = 180100X + 100X = 180200X = 180 min X = 180/200X = 0.90 min By convertiing into seconds, X = 0.90 x 60 secondsX = 54 sec So, time taken for Part A problems is = 54 x 2 x 50 = 5400 seconds= 5400/60sec = 90 minutes.
Q: Question : In a cricket team, the average age of eleven players in 28 years. What is the age of the captain? Statements : a. The captain is eleven years older than the youngest player. b. The average age of 10 players, other than the captain is 27.3 years. c. Leaving aside the captain and the youngest player, the average ages of three groups of three players each are 25 years, 28 years and 30 years respectively. 2199 05b5cc74fe4d2b4197774fb17
5b5cc74fe4d2b4197774fb17- 1All a,b and c followsfalse
- 2Only a and c followsfalse
- 3Either b alone or a & b followstrue
- 4Nonefalse
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Answer : 3. "Either b alone or a & b follows"
Explanation :
Answer: C) Either b alone or a & b follows Explanation: From statement (b)Average of 11 players = 11 x 28 = 308Average of 10 players = 10 x 27.3 = 273Age of captain = 308 - 273 = 35. From the Statement (a) we can say that captain's age (C) = y + 11 ...(1) where y-youngers ageFrom the statement (c),the averge age of 3groups of 3players each was given,It means total 9 players age was given indirectly,1st group: 25 x 3 = 752nd group: 28 x 3 = 843rd group: 30 x 3 = 90Total is 75 + 84 + 90 = 249Now {C + Y + (9 players age sum)}/11 = 28Y + 11 + Y + (249) = 28 x 11=3082Y+260=3082Y = 308-260 = 40 ==> Y=24 ==> C(captain's age)= Y+11 = 24+11 = 35 Therefore, statement b alone or a & c only is the answer.
Q: If a man buys 1 lt of milk for Rs.12 and mixes it with 20% water and sells it for Rs.15, then what is the percentage of gain ? 1505 05b5cc74fe4d2b4197774fb12
5b5cc74fe4d2b4197774fb12- 125%true
- 230%false
- 317%false
- 419%false
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Answer : 1. "25%"
Explanation :
Answer: A) 25% Explanation: He has gain = 15 - 12 = 3,Gain% = (3/12) x 100 = (100/4) = 25.He has 25% gain.
Q: What is the smallest number by which 2880 must be divided in order to make it into a perfect square ? 1417 05b5cc74fe4d2b4197774fb0d
5b5cc74fe4d2b4197774fb0d- 12false
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Answer : 4. "5"
Explanation :
Answer: D) 5 Explanation: By trial and error method, we get2880/3 = 960 is not a perfect square2880/4 = 720 is not a perfect square2880/5 = 576 which is perfect square of 24Hence, 5 is the least number by which 2880 must be divided in order to make it into a perfect square.
Q: (3x + 2) (2x - 5) = ax² + kx + n. What is the value of a - n + k ? 1541 05b5cc74fe4d2b4197774fafe
5b5cc74fe4d2b4197774fafe- 14false
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- 35true
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Answer : 3. "5"
Explanation :
Answer: C) 5 Explanation: (3x + 2) (2x - 5) = ax2+kx+n ...............(1) But (3x + 2)(2x - 5) = 6x2-11x-10........(2) so by comparing (1) & (2), we get a= 6, k= -11 , n= -10 (a - n + k) = 6 + 10 - 11 = 5.
Q: In a race of 200 m, A can beat B by 31 m and C by 18 m. In a race of 350 m, C will beat B by ? 1276 05b5cc74fe4d2b4197774faf4
5b5cc74fe4d2b4197774faf4- 125 mtrue
- 221 mfalse
- 322 mfalse
- 419 mfalse
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Answer : 1. "25 m"
Explanation :
Answer: A) 25 m Explanation: A:B = 200 : 169A:C = 200 : 182 CB = CA×AB 182200×200169 => 182:169 When C covers 182 m , B Covers 169 mWhen C covers 350 m , B Covers 169182×350=> 325 m So C beats B by (350 - 325) = 25 m.