GRE Practice Question and Answer
8Q: Five plays P, Q, R, S and T were organised in a week from Monday to Saturday with one play each day and no play was organised on one of these days. Play S was organised before Thursday but after Monday. Play T was organised on Saturday. Play R was not organised on the first day. Play Q was organised on the next day on which play R was organised. Play P was organised on Tuesday. 1) On which day was play Q organised ? 2) On which day was no play organised ? 3) Which play was organised on Thursday ? 4418 05b5cc736e4d2b4197774f855
5b5cc736e4d2b4197774f855- Show AnswerHide Answer
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Answer :
Explanation :
Day Play Monday No playTuesday PWednesday SThursday RFriday QSaturday T Answers : From the above table : 1) On Friday play Q was organised. 2) On Monday Noplay was organised. 3) On Thursday Play R was organised.
Q: If 'x' means '-', '÷' means '+', '-' means '÷' and '+' means 'x', then 24 - 4 ÷ 6 x 3 + 4 = ? 5792 05b5cc736e4d2b4197774f856
5b5cc736e4d2b4197774f856- 10true
- 21false
- 32false
- 43false
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Answer : 1. "0"
Explanation :
Answer: A) 0 Explanation: From the given information in the question24 ÷ 4 + 6 - 3 x 4 6 + 6 - 12 = 0
Q: Rajitha invested 25% more than Santhosh. Santhosh invested 30% less than Raju, who invested Rs. 6,000. What is the ratio of the amount that Rajitha invested to the total amount invested by all of them together ? 1315 05b5cc736e4d2b4197774f850
5b5cc736e4d2b4197774f850- 125 : 114false
- 235 : 103true
- 315 : 108false
- 441 : 94false
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Answer : 2. "35 : 103"
Explanation :
Answer: B) 35 : 103 Explanation: Santhosh's investment = 6000 x 70/100 = Rs.4200Rajitha's investment = 4200 x 5/4 = Rs.5250Therefore, total amount invested = 6000 + 4200 + 5250 = Rs.15450.Required ratio = 5250 : 15450 = 35 : 103.
Q: 'BE' is related to 'GJ' in the same way as 'PS' is related to ? 1772 05b5cc736e4d2b4197774f84b
5b5cc736e4d2b4197774f84b- 1VXfalse
- 2TUfalse
- 3UXtrue
- 4TVfalse
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Answer : 3. "UX"
Explanation :
Answer: C) UX Explanation: Each corresponding letter moves five places forward in the alphabet.Here as BE is related to GJ then PS will relate to UX.
Q: The perimeter of a square is equal to twice the perimeter of a rectangle of length 8cm and breadth 7cm. What is the circumference of a semicircle whose diameter is equal to the side of the square ? 1257 05b5cc736e4d2b4197774f841
5b5cc736e4d2b4197774f841- 155.12 cmfalse
- 222.54 cmfalse
- 342.51 cmfalse
- 438.57 cmtrue
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Answer : 4. "38.57 cm"
Explanation :
Answer: D) 38.57 cm Explanation: We know that perimeter of rectangle = 2(l+b) = 2(8+7)= 30cmGiven perimeter of square is twice the perimeter of rectangle = 2(30) = 60cmTherefore, side of the square is = 1/4 x 60 = 15cmCircumference of the required semicircle = πr + 2r = 227× 152 + 2×152 = 23.57 + 15 = 38.57cm.
Q: Find the wrong number from the following series ?7 18 40 106 183 282 403 4830 05b5cc736e4d2b4197774f846
5b5cc736e4d2b4197774f846- 118false
- 2183false
- 340true
- 4106false
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Answer : 3. "40"
Explanation :
Answer: C) 40 Explanation: The given series follows the rule,+(11x1), +(11x3), +(11x5), +(11x7), +(11x9),.... So starting from 7, 7 + 11 = 18, 18 + 33 = 51, 51 + 55 = 106, ...So wrong number is 40 which is to be 51.
Q: Find the wrong number from the following series ?37 47 52 67 87 112 142 5681 05b5cc736e4d2b4197774f837
5b5cc736e4d2b4197774f837- 187false
- 247true
- 352false
- 467false
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Answer : 2. "47"
Explanation :
Answer: B) 47 Explanation: The given series follows the rule,+(5x1), +(5x2), +(5x3), +(5x4), +(5x5),.... So starting from 37, 37 + 5 = 42, 42 + 10 = 52, 52 + 15 = 67, 67 + 20 = 87,...So wrong number is 47 which is to be 42.
Q: The ratio of speeds of a car, a train and a bus is 5:9:4. The average speed of the car, the bus and the train is 72 km/hr together. What is the average speed of the car and the train together ? 1542 05b5cc736e4d2b4197774f83c
5b5cc736e4d2b4197774f83c- 184 km/hrtrue
- 296 km/hrfalse
- 372 km/hrfalse
- 460 km/hrfalse
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Answer : 1. "84 km/hr"
Explanation :
Answer: A) 84 km/hr Explanation: Let the speeds of the car, train and bus be 5x, 9x and 4x km/hr respectively.Average speed = 5x + 9x + 4x/3 = 18x /3 = 6x km/hr.Also, 6x = 72 => x = 12 km/hrTherefore, the average speed of the car and train together is = 5x+9x2= 7x = 7 x 12 = 84 km/hr.