IIT JEE Practice Question and Answer

Q: Two candidates fought in a municipality election. One of them got 54% of the total votes pooled and won by 1080 votes. What was the total number of votes polled ? 1073 0

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    12000
    Correct
    Wrong
  • 2
    13500
    Correct
    Wrong
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    15400
    Correct
    Wrong
  • 4
    11000
    Correct
    Wrong
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Answer : 2. "13500"
Explanation :

Answer: B) 13500 Explanation: Given in municipality election 54% votes have won by 1080   Let the total number of votes be x.    54x100 - 46x100 = 1080   8x = 108000   x = 13,500   Therefore, total number of votes = 13,500.

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Answer : 4. "321"
Explanation :

Answer: D) 321 Explanation: No. of people who read Hindu = 285No. of people who read TOI = 127No. of people who read IE = 212Now, No. of people who read Hindu and TOI both is = 20No. of people who read TOI and IE both is = 35No. of people who read Hindu and IE both is = 29Let No. of people who read Hindu , TOI and IE all is = x ;So, only Hindu is = 285-20-29-x = 236-x ;Only TOI is = 127-20-35-x = 72-x ;Only IE is = 212-35-29-x = 148-x ;Now, 236-x + 72-x + 148-x + 20 + 29 + 35 + x + 50 = 500 590 -2x = 500 So, x = 45 this is the value who read all the 3 dailies.So, No. of people who read only one paper is = 236-45 + 72-45 + 148-45 = 191 + 27 + 103 = 321.

Q: If there are 150 questions in a 3 hr examination. Among these questions 50 are type A problems, which requires twice as much as time be spent on the rest of the type B problems. How many minutes should be spent on type A problems ? 3548 0

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    75 min
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    82 min
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    Wrong
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    90 min
    Correct
    Wrong
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    101 min
    Correct
    Wrong
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Answer : 3. "90 min"
Explanation :

Answer: C) 90 min Explanation: Let X = Time taken for each of Type B Problems(100 Problems)And 2X = Time taken for each of Type A problems(50 problems) Total time period = 3hrs = 3 x 60min = 180 minutes 100X + 50(2X) = 180100X + 100X = 180200X = 180 min X = 180/200X = 0.90 min By convertiing into seconds, X = 0.90 x 60 secondsX = 54 sec So, time taken for Part A problems is = 54 x 2 x 50 = 5400 seconds= 5400/60sec = 90 minutes.

Q: Sripad has scored average of 65 marks in three objects. In no subjects has he secured less than 58 marks. He has secured more marks in Maths than other two subjects. What could be his maximum score in Maths ? 1460 0

  • 1
    79
    Correct
    Wrong
  • 2
    77
    Correct
    Wrong
  • 3
    76
    Correct
    Wrong
  • 4
    73
    Correct
    Wrong
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Answer : 1. "79"
Explanation :

Answer: A) 79 Explanation: Assuming Sripad has scored the least marks in subject other than science,Then the marks he could secure in other two are 58 each.Since the average mark of all the 3 subject is 65.i.e (58+58+x)/3 = 65116 + x = 195x = 79 marks. Therefore, the maximum marks he can score in maths is 79.

Q: If a man buys 1 lt of milk for Rs.12 and mixes it with 20% water and sells it for Rs.15, then what is the percentage of gain ? 1505 0

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    25%
    Correct
    Wrong
  • 2
    30%
    Correct
    Wrong
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    17%
    Correct
    Wrong
  • 4
    19%
    Correct
    Wrong
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Answer : 1. "25%"
Explanation :

Answer: A) 25% Explanation: He has gain = 15 - 12 = 3,Gain% = (3/12) x 100 = (100/4) = 25.He has 25% gain.

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Answer : 3. "Either b alone or a & b follows"
Explanation :

Answer: C) Either b alone or a & b follows Explanation: From statement (b)Average of 11 players = 11 x 28 = 308Average of 10 players = 10 x 27.3 = 273Age of captain = 308 - 273 = 35. From the Statement (a) we can say that captain's age (C) = y + 11 ...(1) where y-youngers ageFrom the statement (c),the averge age of 3groups of 3players each was given,It means total 9 players age was given indirectly,1st group: 25 x 3 = 752nd group: 28 x 3 = 843rd group: 30 x 3 = 90Total  is 75 + 84 + 90 = 249Now {C + Y + (9 players age sum)}/11 = 28Y + 11 + Y + (249) = 28 x 11=3082Y+260=3082Y = 308-260 = 40 ==> Y=24 ==> C(captain's age)= Y+11 = 24+11 = 35 Therefore, statement b alone or a & c only is the answer.

Q: What is the smallest number by which 2880 must be divided in order to make it into a perfect square ? 1418 0

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    2
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    3
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    Wrong
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    4
    Correct
    Wrong
  • 4
    5
    Correct
    Wrong
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Answer : 4. "5"
Explanation :

Answer: D) 5 Explanation: By trial and error method, we get2880/3 = 960 is not a perfect square2880/4 = 720 is not a perfect square2880/5 = 576 which is perfect square of 24Hence, 5 is the least number by which 2880 must be divided in order to make it into a perfect square.

Q: (3x + 2) (2x - 5) = ax² + kx + n. What is the value of  a - n + k ? 1541 0

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    4
    Correct
    Wrong
  • 2
    1
    Correct
    Wrong
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    5
    Correct
    Wrong
  • 4
    3
    Correct
    Wrong
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Answer : 3. "5"
Explanation :

Answer: C) 5 Explanation: (3x + 2) (2x - 5) = ax2+kx+n ...............(1)   But (3x + 2)(2x - 5) = 6x2-11x-10........(2)   so by comparing (1) & (2),   we get a= 6, k= -11 , n= -10   (a - n + k) = 6 + 10 - 11 = 5.

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