Answer: B) 2 Explanation: Given that x = 2+ 223 + 213   So x - 2 = 223 + 213   Now cubing on both sides, we get     => x3-8-6x2+12x = 4 + 2 + 6(x-2)   Therefore, x3-6x2+6x = -6 + 8 = 2

Answer: A) 36 kmph Explanation: Let the speed of goods truck be 'p' kmphDistance covered by goods truck in 10hrs (4+6) = Distance covered by other truck in 4 hrs. 10p = 4 x 90p = 36kmph.Therefore, the speed of the goods truck is p = 36 kmph.

Answer: C) MNPO Explanation: PSRQ --> {16, 19, 18, 17} - next 3 alphabets of "P" is written in reverse orderSVUT --> {19, 22, 21, 20} - next 3 alphabets of "S" is written in reverse order MNPO --> {13, 14, 16, 15} KNML --> {11, 14, 13, 12} - next 3 alphabets of "K" is written in reverse order Except "MNPO", others are not in consecutive order.

Answer: A) 175 Explanation: Let the number of males be 'M'Let the number of females be 'F'From the given conditions,(F-15)=2M.....(i)F=5(M-45).....(ii)By solving the equations (1) & (2) we get M = 80 Then substitute M = 80 in (1)F = 2M + 15F = 2 x 80 + 15=> F = 175Therefore, number of males = 80 and females = 175 in the party.

Answer: C) 11 Explanation: Given the company has 8 SD + 6 SRP + 7 IN = 21 cars + 'x' small cars.Given SD makes 1/4 th of the total fleet.=> 8 = 1/4 (21 + x)=> 32 = 21 + x=> x = 11 Therefore, the company has 11 small cars.

Answer: A) 12 pm Explanation: let 't' be the time after which they met since L starts. Given K is 50% faster than L 50 t + 1.5*50(t-1) = 300 50 t +75 t = 300 + 75 t = 375 / 125 = 3 hrs past the time that L starts So they meet at (9 + 3)hrs = 12:00 noon.

Answer: A) 2893 Explanation: For solving this problem first we would break the whole range in 5 sections 1) From 1 to 9Total number of zero in this range = 0 2) From 10 to 99Total possibilities = 9*1 = 9 ( here 9 is used for the possibilities of a non zero integer) 3) From 100 to 999 - three type of numbers are there in this range a) x00 b) x0x c) xx0 (here x represents a non zero number)Total possibilities for x00 = 9*1*1 = 9, hence total zeros = 9*2 = 18for x0x = 9*1*9 = 81, hence total zeros = 81similarly for xx0 = 81 total zeros in three digit numbers = 18 + 81 +81 = 180 4) From 1000 to 9999 - seven type of numbers are there in this rangea)x000 b)xx00 c)x0x0 d)x00x e)xxx0 f)xx0x g)x0xxTotal possibilities for x000 = 9*1*1*1 = 9, hence total zeros = 9*3 = 27 for xx00 = 9*9*1*1 = 81, hence total zeros = 81*2 = 162 for x0x0 = 9*1*9*1 = 81, hence total zeros = 81*2 = 162for x00x = 9*1*1*9 = 81, hence total zeros = 81*2 = 162 for xxx0 = 9*9*9*1 = 729, hence total zeros = 729*1 = 729for xx0x = 9*9*1*9 = 729, hence total zeros = 729*1 = 729for x0xx = 9*1*9*9 = 729, hence total zeros = 729*1 = 729total zeros in four digit numbers = 27 + 3*162 + 3*729 = 2700thus total zeros will be 0+9+180+2700+4 (last 4 is for 4 zeros of 10000)= 2893

Answer: D) 432 Explanation: There are 600 Kabaddi players4% wear knee band on one legRemaining players = 600 x 0.96 = 576Of the remaining, 25% wear knee bands on both leg and Of the remaining, 75% do not wear knee bands .So players not wearing knee bands = 0.75 x 576 = 576 x 3/4 = 144 x 3 = 432.