Quantitative Aptitude Practice Question and Answer
3 4 Answer : 1. "5 kmph"
4 Answer : 3. "1947"
4 Answer : 1. "226.65"
Q: Buses start from a bus terminal with a speed of 20 km/hr at intervals of 10 minutes. What is the speed of a man coming from the opposite direction towards the bus terminal if he meets the buses at intervals of 8 minutes? 1978 05b5cc60ae4d2b4197774b5b5
5b5cc60ae4d2b4197774b5b5- 15 kmphtrue
- 26 kmphfalse
- 37.5 kmphfalse
- 48 kmphfalse
- Show Answer
- Workspace
- SingleChoice
Answer : 1. "5 kmph"
Explanation :
Answer: A) 5 kmph Explanation: Let p be the speed of man in kmph According to the given data in the question, Distance travelled by bus in 10 min with 20 kmph == Distance travelled by man in 8 min with (20 + p) kmph in opposite direction => 20 x 10/60 = 8/60 (20 + p) => 200 = 160 + 8p => p = 40/8 = 5 kmph.
Q: 82.5% of 2360? 2178 05b5cc60ae4d2b4197774b5a1
5b5cc60ae4d2b4197774b5a1- 11960false
- 21954false
- 31947true
- 41931false
- Show Answer
- Workspace
- SingleChoice
Answer : 3. "1947"
Explanation :
Answer: C) 1947 Explanation: Given 82.5% of 2360 82.5100 x 2360 = 0.825 x 2360 = 1947
Q: Simplify the following equation 55.55 + 155 + 15.55 + 0.5 + 0.05 = ? 2660 05b5cc604e4d2b4197774b4fd
5b5cc604e4d2b4197774b4fd- 1226.65true
- 2196.55false
- 3202.35false
- 4216.66false
- Show Answer
- Workspace
- SingleChoice
Answer : 1. "226.65"
Explanation :
Answer: A) 226.65 Explanation: 55.55 + 155 + 15.55 + 0.5 + 0.05 = ? 55.55 155.00 15.55 0.5 0.05 _______ 226.65 _______ Hence, the value of the given equation 55.55 + 155 + 15.55 + 0.5 + 0.05 = 226.65.