Quantitative Aptitude Practice Question and Answer

Q: What is the equivalent compound ratio of 5:6::7:10::6:5  ? 1688 0

  • 1
    7 : 9
    Correct
    Wrong
  • 2
    9 : 7
    Correct
    Wrong
  • 3
    7 : 4
    Correct
    Wrong
  • 4
    7 : 10
    Correct
    Wrong
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Answer : 4. "7 : 10"
Explanation :

Answer: D) 7 : 10 Explanation: Given 5:6 :: 7:10 :: 6:5 We know that compound ratio is calculated as a:b :: c:d :: e:f(axcxe):(bxdxf) => (5x7x6):(6x10x5)=> (210):(300)= 7:10

Q: In a party there are 5 couples. Out of them 5 people are chosen at random. Find the probability that there are at the least two couples ? 6617 0

  • 1
    6/7
    Correct
    Wrong
  • 2
    19/21
    Correct
    Wrong
  • 3
    7/31
    Correct
    Wrong
  • 4
    5/21
    Correct
    Wrong
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Answer : 4. "5/21"
Explanation :

Answer: D) 5/21 Explanation: Number of ways of (selecting at least two couples among five people selected) = (⁵C₂ x ⁶C₁) As remaining person can be any one among three couples left. Required probability = (⁵C₂ x ⁶C₁)/¹⁰C₅= (10 x 6)/252 = 5/21

Q: Find the simple interest on Rs.600 for 11 months at 5 paisa per month ? 1222 0

  • 1
    Rs. 30
    Correct
    Wrong
  • 2
    Rs. 3.30
    Correct
    Wrong
  • 3
    Rs. 33
    Correct
    Wrong
  • 4
    Rs. 330
    Correct
    Wrong
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Answer : 2. "Rs. 3.30"
Explanation :

Answer: B) Rs. 3.30 Explanation: I = (600x11x5)/100 = 330 Paise = Rs. 3.30

Q: The probability that a number selected at random from the first 100 natural numbers is a composite number is  ? 1316 0

  • 1
    3/2
    Correct
    Wrong
  • 2
    2/3
    Correct
    Wrong
  • 3
    1/2
    Correct
    Wrong
  • 4
    34/7
    Correct
    Wrong
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Answer : 1. "3/2"
Explanation :

Answer: A) 3/2 Explanation: The number of exhaustive events = 100 C₁ = 100. We have 25 primes from 1 to 100. Number of favourable cases are 75. Required probability = 75/50 = 3/2.

Q: If rupee two produces rupees eleven over a period of 30 years, find the rate of simple interest ? 1100 0

  • 1
    17.25 %
    Correct
    Wrong
  • 2
    18.14 %
    Correct
    Wrong
  • 3
    18.33 %
    Correct
    Wrong
  • 4
    17.35 %
    Correct
    Wrong
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Answer : 3. "18.33 %"
Explanation :

Answer: C) 18.33 % Explanation: We know that I = PTR/100 11 = (2x30xR)/100 R = 18.333 %

Q: Raju got married 8years ago. His present age is 6/5 times his age at the time of his marriage  Raju's sister was 10years younger to him at the time of his marriage. The present age of Raju's sister is  ? 3870 0

  • 1
    30
    Correct
    Wrong
  • 2
    32
    Correct
    Wrong
  • 3
    38
    Correct
    Wrong
  • 4
    None
    Correct
    Wrong
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Answer : 3. "38"
Explanation :

Answer: C) 38 Explanation: Let Raju's age at the time of his marriage = X years Then from given data => X + 8 = 6/5 X X = 40. Since got married 8 years ago, his present age  = 48 His sister is 10 years younger => 48 - 10 = 38 years.

Q: 96 is divided into two parts in such a way that seventh part of first and ninth part of second are equal. Find the smallest part ? 3592 0

  • 1
    42
    Correct
    Wrong
  • 2
    54
    Correct
    Wrong
  • 3
    46
    Correct
    Wrong
  • 4
    58
    Correct
    Wrong
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Answer : 1. "42"
Explanation :

Answer: A) 42 Explanation: Let x and y be the two parts of 96. x/7 = y/9 => x:y = 7:9 => The smallest part is = 7/16 x 96 = 42.

Q: A man swims downstream 72 km and upstream 45 km taking 9 hours each time; what is the speed of the current  ? 3430 0

  • 1
    1 kmph
    Correct
    Wrong
  • 2
    3.2 kmph
    Correct
    Wrong
  • 3
    1.5 kmph
    Correct
    Wrong
  • 4
    2 kmph
    Correct
    Wrong
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Answer : 3. "1.5 kmph"
Explanation :

Answer: C) 1.5 kmph Explanation: 72 --- 9 ? ---- 1 => Down Stream = 8 45 ---- 9 ? ---- 1 => Up Stream = 5 Speed od current S = ? S = (8 - 5)/2 = 1.5 kmph.

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