General Math Questions and Answers for SSC Exam

General Math Questions and Answers for SSC Exam
Q :  

The value of (x + y + z)3 – (y + z – x)3 – (z + x – y)3 – (x + y – z)3 is:

(A) 12 xyz

(B) 24 xyz

(C) 36 xyz

(D) 0


Correct Answer : B

Q :  

If x = – 1, then the value of   $$ {1\over x^{99}}+{1\over x^{98}}+{1\over x^{97}}+{1\over x^{96}}+{1\over x^{95}}+{1\over x^{94}}+x $$ is

(A) 1

(B) 0

(C) –2

(D) –1


Correct Answer : C

Q :  

$$ {1\over {^3\sqrt{4}+{^3\sqrt{2}}}+1}=a^3\sqrt{4}+ b^3\sqrt{2}+c $$ and a, b, c are rational numbers, then a + b + c is equal to

(A) 0

(B) 1

(C) 2

(D) 3


Correct Answer : A

Q :  

If x = 2 - 21/3 + 22/3, then the value of x3– 6x2 + 18x + 18 is

(A) 22

(B) 33

(C) 40

(D) 45


Correct Answer : C

Q :  

If a3 – b3 – c3 – 3abc = 0, then 

(A) a = b = c

(B) a + b + c = 0

(C) a + c = b

(D) a = b + c


Correct Answer : D

Q :  

If p, q, r are all real numbers, then (p – q)3 + (q – r)3 + (r – p)3 is equal to 

(A) (p – q) (q – r) (r – p)

(B) 3(p – q) (q – r) (r – p)

(C) 0

(D) 1


Correct Answer : B

Q :  

If a = 2·361, b = 3·263 and c = 5·624, then the value of a3 + b3 – c+ 3abc is

(A) 35·621

(B) 0

(C) 19·277

(D) 1


Correct Answer : B

Q :  

If the sum of {a\over b}and its reciprocal is 1 and a ≠ 0, b ≠ 0, then the value of a3 + b3 is

(A) 2

(B) -1

(C) 0

(D) 1


Correct Answer : C

Q :  

The average of 21 consecutive natural numbers is 53. What is the value of the smallest of these 21 numbers?

(A) 42

(B) 41

(C) 43

(D) 44


Correct Answer : C

Q :  

A shopkeeper buys three products a, b, c and sells them at 20%, 30%, 40% profit, respectively. What is ratio of the selling price of these products, if the ratio of their cost prices is 4:3 :2?

(A) 48 : 39 : 28

(B) 34 : 54 : 12

(C) 24 : 39 : 14

(D) 56 : 26 : 21


Correct Answer : A

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    Rajesh Bhatia

    A Writer, Teacher and GK Expert. I am an M.A. & M.Ed. in English Literature and Political Science. I am highly keen and passionate about reading Indian History. Also, I like to mentor students about how to prepare for a competitive examination. Share your concerns with me by comment box. Also, you can ask anything at linkedin.com/in/rajesh-bhatia-7395a015b/.

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