How to Solve Calendar Problems - Calendar Aptitude Questions With Solution For Bank Exams

Hello Candidates,

Most of the students are puzzled while solving calendar problems because they don't know how to solve calendar problems. If you are facing the same problems, you need to know about calendar aptitude questions with solutions for SSC and bank exams.

Here, in this blog, you can learn the simple way to solve calendar-based problems with examples and can improve your performance and preparation level greatly. Keep practicing and solve as many questions as you can, based on the same topic. 

You can take help of calendar aptitude questions and answers also for your preparation. As well as you can understand easily Tricks to solve Calendar Questions by visit here.

How to Solve Calendar Problems for Competitive Exams??

Q.1. January 1, 2007, was Monday. What day will be on Jan. 1, 2008?

Solution: The year 2007 is an ordinary year. So, it has 1 odd day.

1^st day of the year 2007 was Monday.

1^st day of the year 2008 will be 1 day beyond Monday.

Hence, it will be Tuesday.

Q.2. January 1, 2008, is Tuesday. What day will be on Jan. 1, 2009?

Solution: The year 2008 is a leap year. So, it has 2 odd days.

1^st day of the year 2008 is Tuesday (Given).

So, 1^st day of the year 2009 is 2 days beyond Tuesday.

Hence, it will be Thursday.

Q.3. On 8^th Dec 2007 falls Saturday. What day of the week was it on 8^th Dec. 2006?

Solution: The year 2006 is an ordinary year. So, it has 1 odd day.

So, the day on 8^th Dec 2007 will be 1 day beyond the day that of 8th Dec 2006.

But, 8th Dec 2007 is Saturday.

∴ 8^th Dec 2006 is Friday.

Q.4. On 6^th March, 2005 Monday falls. What was the day of the week on 6^th March 2004?

Solution 

The year 2004 is a leap year. So, it has 2 odd days.

∴ The day on 6^th March 2005 will be 2 days beyond the day that on 6^th March 2004.

But, 6^th March 2005 is Monday.

∴ 6^th March 2004 is Saturday

Q.5. The calendar for the year 2007 will be the same for the year:

Solution

Count the number of odd days from the year 2007 onwards to get the sum equal to 0 odd days.

Year       Odd day               

2007       1

2008       2

2009       1

2010       1

2011       1

2012       2

2013       1

2014       1

2015       1

2016       2

2017       1

Sum = 14 odd days ≡ 0 odd day.

∴ Calendar for the year 2018 will be the same as for the year 2007.                                  

Q.6.Today is Monday. After 61 days, it will be 

Solution 

Each day of the week is repeated after 7 days

So, after 63 days, it will be Monday.

∴ After 61 days, it will be Saturday.

Q.7. Which of the following is not a leap year?

(a) 700 (b) 800 (c) 1200 (d) 2000

Solution 

The century divisible by 400 is a leap year.

∴ The year 700 is not a leap year.

Q.8. How many days are there in x weeks x days?

Solution 

x weeks x days = (7x + x) days = 8x days.

Q.9. It was Sunday on Jan 1, 2006. What was the day of the week on Jan 1, 2010?

Solution

On 31^st December, 2005 it was Saturday.

Number of odd days from the year 2006 to the year 2009

= (1+1+2+1) =5 days

∴ On 31^st December 2009, it was Thursday.

Thus, on 1^st Jan, 2010 it is Friday.

Q.10. On 8^th Feb, 2005 it was Tuesday. What was the day of the week on 8^th Feb, 2004?

Solution 

The year 2004 is a leap year. It has 2 odd days.

∴ The day on 8^th Feb, 2004 is 2 days before the day on 8^th Feb, 2005.

Hence, this day is Sunday.

I hope these solutions give you help in your preparation and your competitive exam. If you have any doubt or want to ask anything regarding calendar aptitude questions with solution, you can ask me in the comment section.

All the best !