Inserting the Missing Character Questions for Competitive Exams

Vikram Singh4 years ago 23.6K Views Join Examsbookapp store google play
inserting the missing Character Questions

Find the missing character from among the given alternatives.

Q.1.

(A) 860

(B) 1140

(C) 2880

(D) 3240


Ans .   C


Clearly, moving clockwise, we observe the following pattern:

4 × 1 = 4;  4 × 2 = 8; 8 × 3 = 24; 24 × 4 = 96; 96 × 5 = 480

So, required number = (480 × 6) = 2880.

Hence the answer is (C)

Q.2.

(A) M

(B) P

(C) Q

(D) S


Ans .   B


Putting A = 1, B = 2, C = 3, D = 4,…………………..,X = 24, Y = 25, Z = 26, we have :

F + P = 6 + 16 = 22; G + N = 7 + 14 = 21; J + E = 10 + 5 = 15.

Since K = 11, so value corresponding to missing letter = ( 27 – 11 ) = 16.

So, the missing letter is the 16th letter of the English alphabet, which is P. Hence, the answer is (b).

Q.3.

(A) 22

(B) 30

(C) 32

(D) None of these


Ans .   C


$$Clearly, \ we \ have\ : {5×6×4\over 10}= 12; \ {6×7×5\over21} = 21$$

  $$So, \ missing \ number = {4×8×10\over 10}=32$$

  $$Hence \ the \ answer \ is \ (C)$$

Q.4.

(A) 42

(B) 46

(C) 48

(D) 50


Ans .   B


We have : (8 × 6) – (2 × 6) = 36, (7 × 8) – (2 × 5) = 46.

Missing number = (7 × 10) – (4 × 6) = 46.

Hence, the answer is (b).

Q.5.

(A) 12

(B) 25

(C) 48

(D) 52


Ans .   B


We have : ( 56 +15) – (22+8) = 41, (46+9) – (10+6) = 39.

So, missing number = (34+11) – (14+6) = 25.

Hence, the answer is (b).

Q.6.

(A) 7

(B) 25

(C) 49

(D) 129


Ans .   B


We have : (16 – 6)2 + (5 – 2)2 = 102 +32 = 109; (22 – 15)2+ (21 – 19)2 = 72 + 22 = 53.

So, missing number = (17 – 13)2 + (51 – 48)2 = 42 + 32 =25.

Hence, the answer is (b)

Q.7.

(A) 49

(B) 50

(C) 51

(D) 52


Ans .   C


In the first column, (4 × 7) – 1 = 27.

In the second column, ( 5 × 8) – 2 = 48.

So, missing number = ( 6 × 9) – 3 = ( 54 – 3) = 51.

Hence, the answer is (C)

Q.8.

(A) 2

(B) 3

(C) 4

(D) 5


Ans .   B


In the first column, 12 × ( 18 ÷ 3) = 72.

In the third column, 16 × ( 32 ÷ 4) = 128

Let the missing number be x. Then, in the second column, we have :

14 × ( 24 ÷ x) = 112 ⟺ 24 ÷ x = 8 ⟺ x = 3.

Hence, the answer is (b).

Q.9. 

(A) P

(B) R

(C) S

(D) V


Ans .  B


Putting A = 1, B = 2, C = 3,…………….., M = 13………………., X = 24, Y = 25, Z = 26, we have :

In the first row, F + I = 6 + 9 = 15 = O.

In the second row, A + J = 1 + 10 = 11 = K.

So, in the third row, missing letter = E + M = 5 + 13 = 18 = R.

Hence, the answer is (b).

Q.10. 

(A) 8C

(B) 12B

(C) 16C

(D) 18C


Ans .   A


In each row, out of the letters A, B and C, each of these must appear once. Also, in each column, the product of the first and third numbers is equal to the second number. So, the missing number will be (2×4) i.e 8 and the missing number letter will be C. Thus the answer is 8C. Hence, the answer is (a).

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    Vikram Singh

    Providing knowledgable questions of Reasoning and Aptitude for the competitive exams.

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