Number Series Problems with Solutions for SSC and Bank Exams

Vikram Singh6 years ago 28.4K Views Join Examsbookapp store google play
number series problems with solution

Number series is an important topic to be asked in the competitive examination. A series is given in this topic, this series is based on a particular pattern of which a number is missing. Which we have to find out. These questions are a little hard but you can easily solve these with the pattern/solutions given here.

Preparation is the foundation of all competitive exams but it will be easy if you will do preparation with selective questions and answers. So, you can also practice Alphabet series questions and answers by one click.

As well as you should know Numbers Problems with Solutions to increase your performance in competitive exams. 

Number Series Problems with Solutions for Competitive Exams


Q.1. 2, 4, 10, 22, 42, 72, ?  

(A) 102   

(B) 106  

(C) 114   

(D) 124  

(E) 132  

Answer: option C

Solution:  

2+12 +1= 4   

4+22 +2= 10   

10+32 +3= 22

22+42 +4= 42   

42+52 +5= 72   

72+62+6 = 114   

Q.2. 4, 2, 2, 4, 16, ?   

(A) 64    

(B) 72  

(C) 96    

(D) 128  

(E) 156  

Answer: option D

Solution:  

4* .5 = 2  

2*1 = 2  

2*2 = 4  

4*4 = 16  

16*8 = 128  

Q.3. 15, 15, 30, 10, 40, ?, 48  

(A) 8    

(B) 20  

(C) 24    

(D) 40

 (E) 60  

Answer: option A

Solution:  

15/1 = 15  

15*2 = 30  

30/3 = 10  

10*4 = 40  

40/5 = 8  

8*6 = 48  

Q.4. 2, 3, 8, 27, 112, ?   

(A) 156   

(B) 224  

(C) 375   

(D) 480  

(E) 565  

Answer: option E

Solution:  

2*1+1 = 3  

3*2+2 = 8  

8*3+3 = 27  

27*4+4 = 112  

112*5+5 = 565  

Q.5. 5, 6, 10, 33, 128, ?   

(A) 375   

(B) 445

 (C) 565  

 (D) 645

 (E) 675  

Answer: option D

Solution:  

5*1+1 = 6  

6*2-2 = 10  

10*3+3 = 33  

33*4-4 = 128  

128*5+5 = 645

Q.6. 27, 50, 192, 1140, 9104, ?  

(A) 90400   

(B) 91020

 (C) 92040  

 (D) 94060  

(E) None of these  

Answer: option B   

Solution:  

27, 50, 192, 1140, 9104, ?   

27*2-4 = 50  

50*4-8 = 192  

192*6-12 = 1140  

1140*8-16 = 9104  

9104*10-20 = 91020

Q.7. 6, 11, 32, 111, 464, ?  

(A) 2345   

(B) 2475  

(C) 2525  

 (D) 3050  

(E) None of these  

Answer: option A   

Solution:  

6, 11, 32, 111, 464, ?   

6*1+5 = 11  

11*2+10 = 32  

32*3+15 = 111  

111*4+20 = 464  

464*5+25 = 2345

Q.8. 2, 12, 36, 80, ?, 252, 392  

(A) 80    

(B) 100  

(C) 120  

 (D) 150  

(E) None of these  

Answer: option D

Solution:  

2, 12, 36, 80, ?, 252, 392   

12+13 = 2  

22+23 = 12  

32+33 = 36  

42+43 = 80  

52+53 = 150  

62+63 = 252  

72+73 = 392

If have any doubt or want to ask anything related number series problems, feel free and ask me in the comment section. Visit on the next page to practice more number series problems with solutions.

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    Vikram Singh

    Providing knowledgable questions of Reasoning and Aptitude for the competitive exams.

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