A and B can do a work together in 18 days. A is three times as efficient as B. In how many days can B alone complete the work?
5Q:
A and B can do a work together in 18 days. A is three times as efficient as B. In how many days can B alone complete the work?
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Answer : 2. "72 days"
Explanation :
Let's denote the work rate of A as "A" and the work rate of B as "B." We know that A is three times as efficient as B, so we can write:
A = 3B
Now, we also know that A and B can do a work together in 18 days. The work rate of A and B combined is the sum of their individual work rates, which can be represented as:
A + B
Since they complete the work in 18 days together, we can write:
(A + B) = 1/18
Now, we want to find how long it would take B alone to complete the work. Let's denote that time as "x" days. The work rate of B alone would be:
B (work rate of B alone) = 1/x
Now, we have two equations:
A = 3B
(A + B) = 1/18
We can substitute the value of A from the first equation into the second equation:
(3B + B) = 1/18
Combine like terms:
4B = 1/18
Now, isolate B by dividing both sides by 4:
B = (1/18) / 4
B = 1/72
So, B's work rate is 1/72 of the work per day. To find how many days B alone can complete the work, take the reciprocal of B's work rate:
x (number of days for B alone) = 1 / (1/72)
x = 72
Therefore, it would take B alone 72 days to complete the work.