Join ExamsbookAnswer : 1. "(1/2)^11"
A fair coin is tossed 11 times. What is the probability that only the first two tosses will yield heads ?5
Q: A fair coin is tossed 11 times. What is the probability that only the first two tosses will yield heads ?
- 1(1/2)^11true
- 2(9)(1/2)false
- 3(11C2)(1/2)^9false
- 4(1/2)false
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Answer : 1. "(1/2)^11"
Explanation :
Answer: A) (1/2)^11 Explanation: Probability of occurrence of an event, P(E) = Number of favorable outcomes/Numeber of possible outcomes = n(E)/n(S) ⇒ Probability of getting head in one coin = ½, ⇒ Probability of not getting head in one coin = 1- ½ = ½, Hence, All the 11 tosses are independent of each other. ∴ Required probability of getting only 2 times heads =122×129=1211