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Q:

A pyramid has an equilateral triangle as its base, of which each side is 8 cm. Its slant edge is 24 cm. The whole surface area of the pyramid (in cm2) is:

  • 1
    $$(16\sqrt {3} \ +24\sqrt {35} \ ) $$
  • 2
    $$(12\sqrt { 3} \ +24\sqrt {35} \ ) $$
  • 3
    $$(24\sqrt { 3} \ +36\sqrt {35} \ ) $$
  • 4
    $$(16\sqrt { 3} \ +48\sqrt {35} \ ) $$
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Answer : 4. "$$(16\sqrt { 3} \ +48\sqrt {35} \ ) $$"

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