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Q: A train moving at 2/3 rd of its normal speed reaches its destination 20 minutes late. Find the normal time taken ?

  • 1
    4/3 hrs
  • 2
    2/3 hrs
  • 3
    3/2 hrs
  • 4
    1/4 hrs
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Answer : 2. "2/3 hrs"
Explanation :

Answer: B) 2/3 hrs Explanation: Let the original speed and time is S and Tthen distance = S x TNow the speed changes to 2/3S and T is T+20As the distance is sameS x T = 2/3Sx(T+20)solving this we get t = 40 minutes =40/60 = 2/3 hour

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