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Given that ΔDEF ~ ΔABC. If the area of ΔABC is 9 cm2 and area of ΔDEF is 12cm2 , BC = 2.1 cm, then the length of EF is:
5Q:
Given that ΔDEF ~ ΔABC. If the area of ΔABC is 9 cm2 and area of ΔDEF is 12cm2 , BC = 2.1 cm, then the length of EF is:
- 1$${{8\sqrt { 2}}\over 5}cm $$false
- 2$${{3\sqrt { 7}}\over 5}cm $$false
- 3$${{4\sqrt { 7}}\over 5}cm $$false
- 4$${{7\sqrt { 3}}\over 5}cm $$true
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