I.$$ {15\over \sqrt {x}}-{2\over \sqrt {x}}=6\sqrt {x}$$
II.$$ {\sqrt {y}\over 4}-{7\sqrt {y}\over \sqrt {12}}={1\over \sqrt {y}}$$
Give answer
(A) x>y
(B) x≥y
(C) x<y
(D) x≤y
(E) x=y or the relationship cannot be established
In the following question two equations numbered I and II are given. You have to solve both the equations and ____
I.$$ {15\over \sqrt {x}}-{2\over \sqrt {x}}=6\sqrt {x}$$
II.$$ {\sqrt {y}\over 4}-{7\sqrt {y}\over \sqrt {12}}={1\over \sqrt {y}}$$
Give answer
(A) x>y
(B) x≥y
(C) x<y
(D) x≤y
(E) x=y or the relationship cannot be established