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I. $$ {\sqrt{6}x^{2}}+(4+\sqrt{15})x+2\sqrt{10}=0$$
II. $$ {y^{2}}-(\sqrt{6}+\sqrt{5})y+\sqrt{30}=0$$
Directions : In each of these questions, two equations numbered I and II with variables x and y are given. You have to solve both the equations to find the value of x and y. Give answer:
1) if x>y
2) if x ≥ y
3) if x<y
4) if x ≤ y
5) if x= y or relationship between x and y cannot be determinedQ:
I. $$ {\sqrt{6}x^{2}}+(4+\sqrt{15})x+2\sqrt{10}=0$$
II. $$ {y^{2}}-(\sqrt{6}+\sqrt{5})y+\sqrt{30}=0$$
- 11false
- 22false
- 33true
- 44false
- 55false
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