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Q:

If $$ {1+sinθ\over {1-sinθ}}={p^{2}\over{q^{2}}}$$, then sec θ is equal to:

  • 1
    $$ {2p^{2}{q^{2}}\over {p^{2}+{q^{2}}}}$$
  • 2
    $${1\over 2}\left({q\over p}+{p\over q} \right)$$
  • 3
    $$ {1\over {p^{2}}}+{1\over {q^{2}}}$$
  • 4
    $$ {p^{2}q^{2}}\over{p^{2}+q^{2}}$$
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Answer : 2. "$${1\over 2}\left({q\over p}+{p\over q} \right)$$"

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