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Q:

If $$ {a^{x}={(x+y+z)^{y}}}, a^{y}=(x+y+z)^{z}  and \ a^{z}=(x+y+z)^{x}$$ then the value of (x +y +z) is

  • 1
    0
  • 2
    $$ {a^{3}} $$
  • 3
    1
  • 4
    a
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Answer : 4. "a"

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