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Q: If a2 + b2 + 64c2 + 16c + 3 = 2(a +b), then the value of 4a7 + b7 + 8c2 is :

  • 1
    $$ {4{1\over 8}}$$
  • 2
    $$ {5{1\over 8}}$$
  • 3
    $$ {4{7\over 8}}$$
  • 4
    $$ {3{1\over 8}}$$
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Answer : 2. "$$ {5{1\over 8}}$$"

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