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Q:

If $$ {sin\ {θ}}={1\over {\sqrt{2}}}$$ then (tanθ+cosθ)=?

  • 1
    $${1\over{\sqrt{2}}}$$
  • 2
    $${2\over{\sqrt{2}}}$$
  • 3
    $${3\over{\sqrt{2}}}$$
  • 4
    $$ {(1+\sqrt{2})\over{\sqrt{2}}}$$
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Answer : 4. "$$ {(1+\sqrt{2})\over{\sqrt{2}}}$$"

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