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If $$ sin(θ+30^0)= {3\over \sqrt { 12} } $$ then find cos2θ :
5Q:
If $$ sin(θ+30^0)= {3\over \sqrt { 12} } $$ then find cos2θ :
- 1$$ {1\over 4} $$false
- 2$$ {3\over 4} $$true
- 3$${\sqrt { 3} \ }\over 2 $$false
- 4$$ {1\over 2} $$false
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