Q: If the binary equivalent of 5.375 in normalised form is 0100 0000 1010 1100 0000 0000 0000 0000, what would be the output of the following program? main() {     float a = 5.375 ;     char *p;     int i;     p = ( char* ) &a ;     for ( i = 0; i <= 3 ; i++ )           printf ( " %02x ", (unsigned char ) p[i] ); }