Join Examsbook
If $$ {x^{4}+x^{2}y^{2}+y^{4}={21\over256}}$$ and $$ {x^{2}+xy+y^{2}={3\over16}}$$ then $$ {2(x^{2}+y^{2})}=?$$
5Q:
If $$ {x^{4}+x^{2}y^{2}+y^{4}={21\over256}}$$ and $$ {x^{2}+xy+y^{2}={3\over16}}$$ then $$ {2(x^{2}+y^{2})}=?$$
- 1$$ {3\over 8}$$false
- 2$$ {5\over 8}$$true
- 3$$ {3\over 4}$$false
- 4$$ {5\over 16 }$$false
- Show AnswerHide Answer
- Workspace